主题：TB代码转换成金字塔，谢谢

zijin:=50000;
length1:=11;
length2:=42;
length3:=53;
length4:=178;

lots:=zijin/Close;
condition1:= close[2] > close[length1]  and close[9] > close[length4] and close[1] > open[1] and close[138]>open[length2] and close[1] > open[length3];