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- 2021-7-4
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楼主 |
发表于 2024-3-27 11:53
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老师,好,
TRA0:=MAX(MAX((CALLSTOCK(STKLABEL,VTHIGH,17,0)-CALLSTOCK(STKLABEL,VTLOW,17,0)),ABS(CALLSTOCK(STKLABEL,VTCLOSE,17,-1)-CALLSTOCK(STKLABEL,VTHIGH,17,0))),ABS(CALLSTOCK(STKLABEL,VTCLOSE,17,-1)-CALLSTOCK(STKLABEL,VTLOW,17,0)));
TRA1:=MAX(MAX((CALLSTOCK(STKLABEL,VTHIGH,17,-1)-CALLSTOCK(STKLABEL,VTLOW,17,-1)),ABS(CALLSTOCK(STKLABEL,VTCLOSE,17,-2)-CALLSTOCK(STKLABEL,VTHIGH,17,-1))),ABS(CALLSTOCK(STKLABEL,VTCLOSE,17,-2)-CALLSTOCK(STKLABEL,VTLOW,17,-1)));
TRA2:=MAX(MAX((CALLSTOCK(STKLABEL,VTHIGH,17,-2)-CALLSTOCK(STKLABEL,VTLOW,17,-2)),ABS(CALLSTOCK(STKLABEL,VTCLOSE,17,-3)-CALLSTOCK(STKLABEL,VTHIGH,17,-2))),ABS(CALLSTOCK(STKLABEL,VTCLOSE,17,-3)-CALLSTOCK(STKLABEL,VTLOW,17,-2)));
ATR:=(TRA0+TRA1+TRA23)/3;
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我用这法在一分钟周期上取得了在三分钟周期上的ATR:=MA(TRA,3);
我像用相同的法,取得ATR:=EMA(TRA,3);
感觉难很多,不好写,老师帮忙写个?谢谢
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